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A bottle with a open mouth contains air at $47 º C$ . The temperature to which the bottle must be heated so that 1/5^th of the mass of air leaves the bottle is

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$80 º$

$127 º C$

$320 º C$

$235 º C$

answer is B.

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Detailed Solution

Here P is atmospheric pressure. Volume V is constant
From PV = mrT, MT = constant
$m_{1} T_{1} = m_{2} T_{2}$
i.e., $m_{1} (273 + 47) = \frac{4 m_{1}}{5} T_{2}$
$Then T_{2} = 400 K and$
$t_{2} = 400 - 273 = 127 º C$

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