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A box contains 6 tickets. Two of the tickets carry a price of Rs.5/- each, the other 4 the price of Rs.1. If one ticket is drawn, the mean value of the price is

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14/3

7/6

7/3

answer is D.

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Detailed Solution

Let $X$ denotes the value of the ticket selected at random from the box
Range of $X$ is ${5, 1} . P (X = 5) = \frac{2}{6} = \frac{1}{3}, P (X = 1) = \frac{4}{6} = \frac{2}{3}$
Mean $= 5 (\frac{1}{3}) + 1 (\frac{2}{3}) = \frac{7}{3}$

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