A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box. Find the probability that it bears a two digit number

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\frac{9}{10}

\frac{3}{10}

answer is A.

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Detailed Solution

Let E be the event of drawing a disc from the box of discs numbered from 1 to 90
Two digit number from 1 to 90 = 10, 11, 12,……, 90
Number of favourable outcomes = 81
Total number of possibles outcomes = 90
Probability P(E)
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Therefore, the probability of a two digit numbered disc from the box of disc numbered from 1 to 90 is

\frac{9}{10}

.
Hence, Option (1) is the correct answer.

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