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Q.

A box contains coupons labelled 1,2,…..,100. Five coupons are picked at random one  after another without replacement. Let the numbers on the coupons are arranged in the  order  x1,x2,....x5. Then the number ways that they satisfying x1>x2>x3 and x3<x4<x5 is

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a

 100C5

b

6.100C5

c

6.95C5

d

 95C5

answer is B.

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Detailed Solution

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x3 is the smallest fixed in the middle divide remaining 4 on either side of x3 in  4C2=6 ways 

  x3  

 

 

the required number of ways =6.100C5

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