A box contains tickets numbered from 1 to 20. If 3 tickets are drawn one by one with replacement then the probability of getting prime number exactly 2 times is

Given a box contains tickets numbered from 1 to 20 and 3 tickets are drawn one by one with replacement.

Now Probability of getting Prime number $=\frac{8}{20}$

Now Probability of getting Prime numbers twice is $=\frac{8}{20}\times \frac{8}{20}\times \frac{12}{20}$

                                                                                          $=\frac{12}{125}$