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A box is accelerating with acceleration $= 20 m / s^{2}$ .A block of mass 10 kg placed inside the box and is in contact with the vertical wall as shown. The friction coefficient between the block and the wall is $μ = 0.6$ and take $g = 10 m / s^{2}$ . Then choose correct option(s)

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The acceleration of the block will be $20 m / s^{2}$

The friction acting on the block will be 100 N

The contact force between the vertical wall and the block will be $100 \sqrt{5} N$

The force between the vertical wall and the block is only electromagnetic in nature.

answer is A, B, C, D.

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Detailed Solution

$N = m a = 100 \times 20 = 200 N$

$f = v R = 0.6 \times 200 = 120 N$

$f = 100 N$

Since $f < f_{1}$ ,so block will not slip down and acceleration of block will aslope be $20 m / s^{2}$ in horizontal direction.

Net contact force:

$F = \sqrt{N^{2} + f^{2}} = \sqrt{200^{2} + 100^{2}} = 100 \sqrt{5} N$

All contact forces are electromagnetic in nature.

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