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Q.

A box of mass 50kg at rest is pulled up on an inclined plane 12m long and 2m high by a constant force of 100N. When it reaches the top of the inclined plane if its velocity is $2 {ms}^{- 1}$ , the work done against friction in joules is $(g = 10 {ms}^{- 2})$

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a

150

b

100

c

50

d

200

answer is B.

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Detailed Solution

$W = \frac{1}{2} {mv}^{2} = \frac{1}{2} \times 50 \times 4 = 100 = 100 J$

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A box of mass 50kg at rest is pulled up on an inclined plane 12m long and 2m high by a constant force of 100N. When it reaches the top of the inclined plane if its velocity is 2 ms-1, the work done against friction in joules is g=10 ms-2