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A boy is sitting on a horizontal platform in the shape of a disc at a distance of 5m from its centre. The boy begins to slip when the speed of wheel exceeds 10 rpm The coefficient of friction between the boy and platform is
(g = 10 ms^–2)

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$π^{2} / 18$

$π / 2$

$π^{2} / 6$

$π / 6$

answer is B.

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Detailed Solution

w = 10×(2π/60) rad/s

w = π/3 rad/s

r = 5m

mw²r = μmg = f

μ = π²/18

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