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A boy moving along a circular path of radius $10 m$ completes $3 / 4^{th}$ of the circle in $10 s$ . The magnitude of speed and distance are

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4.71 m / s, 47.14 m / s

5.71 m / s, 7.14 m / s

47.71 m / s, 4.14 m / s

None of these

answer is A.

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Detailed Solution

A boy moving along a circular path of radius

10 m

completes

3 / 4^{th}

of the circle in

10 s

. The magnitude of speed and distance are

4.71 m / s

and

47.14 m / s

, respectively.
The boy's speed is the distance he travels with respect to time. The distance travelled depends on the path followed by him.

Speed = \frac{Distance}{Time}

The path followed by him is three-fourths of the circumference of the circular path.
Distance

d = \frac{3}{4} \times 2 πr

Here,

r

is the radius of the circular path
Distance

d = \frac{3}{4} \times 2 π (10 m)

= > d = 47.14 m

So, the speed can be calculated as
Speed

v = \frac{47.14 m}{10 s}

= > v = 4.71 m / s

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