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Q.

A boy of mass 50 kg jumps to a height of 0.8 m from the ground then momentum transferred by the ground to boy is :

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a

400 kg m/s

b

500 kg m/s

c

800 kg m/s

d

200 kg m/s

answer is B.

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Detailed Solution

From KE $= \frac{P^{2}}{2 m} = mgh$
$\begin{array}{l} P = \sqrt{2 m^{2} gh} \\ = \sqrt{2 \times (50)^{2} \times 10 \times 0 .8} \\ = 200 kgm / s \end{array}$

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