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Q.

A boy of weight 25kg slides down a rope hanging from the branch of a tree. If the force of friction against him is 50N, the boy’s acceleration is (g=10ms^–2)

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a

12ms^–2

b

2 ms^–2

c

10ms^–2

d

8 ms^–2

answer is C.

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Detailed Solution

$\begin{array}{l} mg - f = ma \Rightarrow 25 \times 10 - 50 = 25 (a) \\ \Rightarrow a = \frac{200}{25} = 8 m / s^{2} \end{array}$

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