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A boy sees a ball go up and then down through a window 2.45 m high. If the total time that ball is in sight in 1s, the height above the window the ball rises is approximately

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2.45m

4.9m

0.3m

0.49m

answer is C.

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Detailed Solution

x = ut + \frac{1}{2} {gt}^{2}

$2.45 = \frac{g}{4}$

$\frac{g}{4} = u (\frac{1}{2}) + \frac{g}{2} {(\frac{1}{2})}^{2}$

$\frac{g}{4} = \frac{u}{2} + \frac{g}{8}$

$\frac{g}{4} = \frac{u}{2}$

$u = \frac{g}{4}$

$h = \frac{u^{2}}{2g}$

$= \frac{1}{2 g} \times \frac{g^{2}}{16}$

$= \frac{g}{32} = \frac{9.8}{32} = 0.3 m$

$h = 0 .3m$

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