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A boy stands between the two walls and claps his hands as shown below :
If ‘x’ is less than 60 m and the time between the first and the second echo is 0.25 s, then calculate the distance ‘x’ (Velocity of sound in air is $344 {ms}^{- 1}$ )

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40 m

36 m

17 m

34 m

answer is D.

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Detailed Solution

Time interval between 1^st and 2^nd echo is 0.25 s.
$\frac{120}{344} - \frac{2 x}{344} = 0 .25 ∴ 120 - 2 x = 86 2 x = 34 x = 17 m$

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