A boy throws a ball of mass 0.5 kg upwards with an initial speed of 14 m/s. The ball reaches a
maximum height of 8m. The amount of energy dissipated by air drag acting on the ball during
the ascent is then,

The greatest height the ball may reach when thrown upwards must first be determined using the equation of motion with regard to the gravitational force constant, g. By calculating the difference between the maximum height and the achieved height, the energy loss may be determined.
Given that, the chain's mass is.

The starting speed is 14 m/s.
The ball may go up to a maximum height of 8 meters.
G=9.8m/s is the gravitational constant.
The gravity-related motion equation is written as,

$H=\frac{u^2}{2g}\dots \dots \left(1\right)$
The energy equation is stated as,
$E=mgh\dots \text{....(2) }$
The ball can only rise to a height of, if there is no air friction or drag.
$H=\frac{u^2}{2g}=\frac{{14}^2}{2\times 9.8}=10 \mathrm{m}$
However, it is a guarantee that the highest point it can ascend to $h=8 \mathrm{m}$
As a result, the energy loss may be estimated as follows:
$E=mg(H-h)\dots .\text{ (3) }$
Substituting the value of h as and the value of H as 10min equation (3), we get
$\mathrm{E}=\mathrm{mg}(\mathrm{H}-\mathrm{h})=0.5\times 9.8(10-8)=9.8 \mathrm{J}$

The energy loss is estimated to be 9.8J.
Hence, the correct answer is option B.