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A boy throws a ball with speed u in a well of depth 14 m as shown. On bounce with bottom of the well the speed of the ball gets halved. What should be the minimum value of u/10 (in m/s) such that ball may be able to reach his hand again? It is given that his hands are at 1 m height from top of the well while throwing and catching. $(g = 10 m / s^{2})$

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answer is 3.

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Detailed Solution

$\frac{u^{2} + 2 g \times 15}{8 g} = 15$

$u^{2} = 90 g$

u = 30

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