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Q.

A boy throws n balls per second at regular time intervals. When the first ball reaches the maximum height he throws the second one vertically up. The maximum height reached by each ball is

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a

$\frac{g}{n^{2}}$

b

$\frac{g}{2 (n - 1)^{2}}$

c

$\frac{g}{n}$

d

$\frac{g}{2 n^{2}}$

answer is B.

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Detailed Solution

For one ball t = 1/n

$\Rightarrow t_{a} = \frac{1}{n} = \frac{u}{g}$
$H = \frac{u^{2}}{2 g} = (\frac{g^{2}}{n^{2}}) \frac{1}{2 g} = \frac{g}{2 n^{2}}$

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