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Q.

A boy throws n balls per second at regular time intervals. When the first ball reaches the maximum height he throws the second one vertically up. The maximum height reached by each ball is

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a

gn2

b

g2(n−1)2

c

gn

d

g2n2

answer is B.

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Detailed Solution

For one ball t = 1/n

⇒ ta=1n=ug
H=u22g=g2n212g=g2n2

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