A boy walks to his school at a distance of 6 km with a constant speed of 2.5kmph and walks back with a constant speed of 4kmph. His average speed for the round trip expressed in kmph is

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\frac{1}{2}

\frac{40}{13}

\frac{24}{13}

answer is B.

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Detailed Solution

Given that a boy walks from house to school with speed

v_{1} = 2.5 kmph

Question Image

Returned from school to house with speed $v_{2} = 4 kmph$

We know

$V_{Avg} = \frac{{2v}_{1} v_{2}}{v_{1} + v_{2}} = \frac{2 \times 2.5 \times 4}{2.5 + 4}$

$\frac{20}{6.5} = \frac{20}{\frac{65}{10}} = \frac{200}{65}$

$V_{Avg} = \frac{40}{13} kmph$

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