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A boy wants to climb down a rope. The rope can withstand a maximum tension equal to two-thirds the weight of the boy. If g is the acceleration due to gravity, the minimum acceleration with which the boy should climb down the rope should be

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$\frac{g}{3}$

$\frac{2 g}{3}$

$g$

$z e r o$

answer is A.

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Detailed Solution

Let a be the minimum acceleration with which the boy must climb down the rope. Then mg –T=ma or T=mg-ma is the maximum tension Now,

$T= \frac{2}{3} mg.Therefore$

$\frac{2}{3} mg = mg - ma$

Which gives $a=g/3$

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