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A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m above level ground. The string breaks and the stone flies off tangentially and strikes the ground after travelling a horizontal distance of 10 m. What is the magnitude of the centripetal acceleration of the stone while in circular motion?

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$163 m / s^{2}$

$64 m / s^{2}$

$15.63 m / s^{2}$

125 $m / s^{2}$

answer is A.

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Detailed Solution

$t = \sqrt{\frac{2 l}{g}} = \sqrt{\frac{2 \times 2.0}{9.8}} = 0.64 s$

$v = \frac{10}{t} = 15.625 \frac{m}{s} a = \frac{v^{2}}{R} = 163 m / s^{2}$

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