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A branch of a circuit is shown in the figure. If current is decreasing at the rate of 103 As-1, then the potential difference between A and B is

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1 V

5 V

10 V

2 V

answer is A.

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Detailed Solution

$\begin{array}{l} V_{R} = iR = 2 \times 7 = 14 V \\ \Rightarrow V_{AB} - V_{R} + e + V = 0 \end{array}$
induced emf,
$e = L \times \frac{di}{dt} \Rightarrow v_{AB} - 14 + 9 + 4 = 0$

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