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Q.

A brass disc at 0°C has a diameter of 50 cm and a hole of diameter 10cm. For Brass α = 18 × 10–6/°C. When the disc is heated to 100°C, the diameter of the hole becomes.

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a

10.180 cm

b

10.81 cm

c

10.8 cm

d

10.018 cm

answer is A.

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Detailed Solution

d1 and d2  are diameters wich can betaken as initial and final lenths then

d2 = d1 [1 + α∆t] = 10[1 + (18 x 10-6) x 100] 
=10(1 + 18 x 10-4) =10.018cm

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