A brass wire of cross sectional area ${2 mm}^{2}$ is suspended from a rigid support and a body of volume $100 {cm}^{3}$ is attached to its other end. If the decrease in the length of the wire is 0.11mm, when the body is completely immersed in water, find the natural length of the wire. $(Y_{brass} = 0. 91 \times 1 0^{11} {Nm}^{- 2}, ρ_{w a t e r} = 1 0^{3} {kgm}^{- 3})$

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

20.43 m

30.43 m

40.43 m

10.43 m

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$a c c o r d i n g t o l a w o f f l o a t a t i o n, b u o y a n t f o r c e = m g$

$\Rightarrow F = m g = V ρ_{l} g = 100 \times 10^{- 6} \times 1000 \times 9.8 = 0.98 N$

$ℓ = \frac{y A e}{F} = \frac{0.91 \times 10^{11} \times 2 \times 10^{- 6} \times 0.11 \times 10^{- 3}}{0.98} = 0.204 \times 10^{2} m$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test