A brass wire of cross sectional area ${\text{2 mm}}^2$  is suspended from a rigid support and a body of volume $\text{1}00{\text{ cm}}^3$  is attached to its other end. If the decrease in the length of the wire is 0.11mm, when the body is completely immersed in water, find the natural length of the wire. $({\text{Y}}_{\text{brass}}=0.\text{91}\times \text{1}{0}^{\text{11}}{\text{Nm}}^{-2},{\rho }_{water}=\text{1}{0}^{\text{3}}{\text{kgm}}^{–\text{3}})$