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Q.

A bromoalkane ‘X’ reacts with magnesium in dry ether to form compound ‘Y’. The reaction of ‘Y’ with methanal followed by hydrolysis yield an alcohol having molecular formula, C4H10O. The compound ‘X’ is

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a

1-bromopropane

b

bromomethane

c

2-bromopropane 

d

bromoethane

answer is C.

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