A bulb in an electric circuit glows due to:

Here, we may utilize the idea of the heating impact of a Joule on a specific metallic conductor through which electric current is transmitted to describe how much heat is produced when the conductor is subjected to electric current.

Ohmic heating is another name for the Joule heating phenomenon. According to the effect, anytime an electric current flows through a metallic conductor, the free electron flow starts to travel quickly and heats the conductor.
Joule's first law states that the heat produced in a metallic conductor when electricity is applied to it is inversely proportional to the product of that conductor's resistance and the square of the current.

Mathematically, we have, $P\propto I^{2}R$, P is the quantity of heat that the metallic conductor produces when an electric current is applied to it.
The metallic conductor's electrical current, I, is measured in amps.
The metallic conductor's resistance, or R, is what allows electrical current to flow through it.
I and R's SI units are amperes (A) and ohms, respectively $\left(\Omega \right)$.

As a result, when an electric current is delivered through the filament of the bulb, the high resistance quality of the filament causes it to heat up first, and then the filament comes into touch with the chemical within the seated bulb, which causes the bulb to glow. Thus, the heating action of current causes a bulb to light in an electric circuit.
In light of the foregoing justification, 

Hence, the correct answer is option B.