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Q.


A bulb is connected to a battery of potential difference Question Image and internal resistance Question Image. A steady current of Question Image flows through the circuit. Calculate:


(i) The total energy supplied by the battery for 10 minutes will be ____J.


(ii) The energy dissipated in the bulb in 10 minutes is ____J.


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Detailed Solution

Concept- To answer the questions, we must first put down all the relevant data and values that are provided, followed by the formulas we must discover. The Joule unit of energy is used.
Given values: Voltage, Question Image, Resistance of the battery, Question Image, Current, Question Image(i) Energy supplied by the battery: We have the formula to find the energy supplied when voltage, resistance and current is given,and the time for supplying energy by the battery is 10 minutes i.e.. 600 seconds.
To determine the energy provided, we must first determine the resistance:
Question ImageTherefore, Question ImageSo, the total energy supplied by the battery in 10 minutes is 1200 J . Total resistance R=8Ω
(ii) Resistance of the battery, Question ImageSo, the Resistance of the bulb, Question Image.
In the bulb, energy was lost after 10 minutes:
Question ImageQuestion ImageQuestion ImageSo, the energy dissipated in the bulb in 10 minutes is Question Image.
Hence the answers are 1200J and 825J respectively.
 
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