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A bullet loses 25% of its initial kinetic energy after penetrating through a distance of 2cm in a target. The further distance it travels before coming to rest is

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$\frac{8}{3}$ cm

6cm

2 cm

1 cm

answer is D.

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Detailed Solution

$F S = Δ K E$

$S \propto Δ K E$

$\frac{s_{1}}{s_{2}} = \frac{Δ K E_{1}}{Δ K E_{2}}$

$\frac{2}{s_{2}} = \frac{\frac{1}{4}}{\frac{3}{4}} \Rightarrow s_{2} = 6 c m$

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