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Q.

A bullet moving at 250 m/s penetrates 5 cm into a tree limb before coming to rest. Assuming that the force exerted by the tree limb is uniform, find its magnitude. Mass of the bullet is 10g.

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a

5260 N

b

4320 N

c

6520 N

d

6250 N

answer is D.

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Detailed Solution

u=250 m/s,v=0,x=5 cm=0.05 m

Giving,  a=(250 m/s)2−022×0.05 m=625000 m/s2

The force on the bullet is  F=ma=6250 N

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