A bullet moving with a velocity of $10 m s^{- 1}$ is brought to rest after penetrating a wooden plank of 4 cm thickness. The retardation of the bullet is

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$- 1250 m s^{- 2}$

$- 1200 m s^{- 2}$

$1200 m s^{- 2}$

$1250 m s^{- 2}$

answer is D.

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Detailed Solution

$W e k n o w v^{2} - u^{2} = 2 a s \Rightarrow {(0)}^{2} - {(10)}^{2} = 2 a (4 \times 10^{- 2}) \Rightarrow a = \frac{- 100}{8 \times 10^{- 2}} = - 1250 m s^{- 2} r e t r a d a t i o n (- a) = 1250 m s^{- 2}$

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