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Q.

A bullet moving with a velocity of 10 ms−1is brought to rest after penetrating a wooden plank of 4 cm thickness. The retardation of the bullet is

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a

1200 ms−2

b

−1200 ms−2

c

−1250 ms−2

d

1250 ms−2

answer is D.

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Detailed Solution

Initial velocityu=10m/s, Final velocity v = 0, Displacement

s=4cm=4×10−2m

a =?

We know v2−u2=2as

⇒(0)2−(10)2=2a(4×10−2)

retardation(−a)=1250ms−2

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