A bullet of mass 0.02 kg travelling horizontally at $50 m / s$ hits a stationary block of wood of mass 4 kg, passes through it and emerges horizontally with a speed of $20 m / s$ . If the block is free to move on a smooth horizontal plane, the speed with which it is moving after the bullet had passed through it is

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$0. 35 m / s$

$0. 15 m / s$

$0. 75 m / s$

$0. 5 m / s$

answer is B.

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Detailed Solution

$m_{1} u_{1} + 0 = m_{1} v_{1} + m_{2} v_{2}$

$0.02 \times 50 + 0 = 0.02 \times 20 + 4 v_{2}$

$0.02 \times 30 = 4 v_{2}$

$v_{2} = 0.15 m / s$

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