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A bullet of 10 g leaves the barrel of gun with a velocity of 600 m/s. if the barrel of gun is 50cm long and mass of gun is 3kg, then value of impulse supplied to the gun will be:

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36 Ns

12 Ns

6 Ns

3 Ns

answer is C.

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Detailed Solution

If u is speed w.r.t barrel and V is recoil speed of gun, then
$V = \frac{mu}{M + m}$ $impulse J = Δ P=MV-0= \frac{Mmu}{M + m} = \frac{3 \times (10 \times 10^{- 3}) (600)}{(3 + 10 \times 10^{- 3})}$ $= 6 N . s$

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