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A bullet of mass 10 g and speed $500 m s^{- 1}$ is fired into a door and gets embedded exactly at the centre of the door. The door is 1 m wide and weighs 12 kg. The door is hinzed at one end and rotates about a vertical axis. The angular speed of door just after the bullet embeds into it.

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$0.625 r a d s^{- 1}$

$0.450 r a d s^{- 1}$

$0.800 r a d s^{- 1}$

$0.280 r a d s^{- 1}$

answer is A.

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Detailed Solution

$m v \frac{L}{2} = \frac{M L^{2}}{3} . ω$

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