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Q.

A bullet of mass 10 g fired from a gun hits a stationary wooden block with velocity 150 m/s and comes to rest in 0.03 s. What distance the bullet will enter into the wooden block before coming to rest?


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a

2.5 m

b

2.25 m

c

2 m

d

3 m 

answer is B.

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Detailed Solution

From the equations of motion,
v - u = at where v, u, a and t are the final velocity, initial velocity, acceleration and time taken respectively.
On substituting the given values, we get
=> v - u = at
=> 0 - 150 = a x 0.03
=> a = -5000 m/s2
Now, the distance travelled is given by
=> v2 - u2 = 2as
=> 02 - 1502 = 2 x (-5000) x s
=> (-10000)s = -22500
=> s = 2.25 m
 
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