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Q.

A bullet of mass 10×10–3kg moving with a speed of 20ms–1 hits an ice block (0°C) of 990g kept at rest on a frictionless floor and gets embedded in it. If ice takes 50% of K.E, the amount of ice melted (in grams) approximately is (J=4.2J/cal) (Latent heat of ice = 80cal/g)

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a

3 × 10–3

b

6 × 10–3

c

6

d

3

answer is D.

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Detailed Solution

mb=10−2kg;V=20m/s1212mbV2=Jmiec Lice 14×10−2×400=4.2mice ×80mice =1366=0.0029≈0.003=3×10−3gm

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