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A bullet of mass 200 g having initial kinetic energy 90 J is shot inside a long swimming pool as shown in the figure. If it's kinetic energy reduces to 40 J within 1s, the minimum length of the pool, the bullet has a travel so that it completely comes to rest is

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25 m

45 m

125 m

90 m

answer is A.

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Detailed Solution

$u = \frac{1}{0.2} \sqrt{2 \times 0.2 \times 90} = 30 m / s$

$v = \frac{1}{0.2} \sqrt{2 \times 0.2 \times 40} = 20 m / s$

$a = \frac{20 - 30}{1} = - 10 m / s^{2}$

$s = \frac{- u^{2}}{2 a} = 45 m$

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