A bullet of mass of 50 g is fired horizontally with a velocity of 200 m/s from a pistol of mass of 5 kg. Calculate the recoil velocity of the piston.

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1.5 m/s

2.5 m/s

2 m/s

3 m/s

answer is C.

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Detailed Solution

It is known that the recoil velocity is given by
vG = -(mBvB) / mG
where vG, mB, vB and mG are the recoil velocity, the mass of the bullet, velocity of the bullet and the mass of the gun respectively.
On substituting the values given we get the recoil velocity as
=> vG = -(mBvB) / mG
=> vG = -(0.05 * 200) / 5
=> vG = -2 m/s

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