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A bullet when fired at a target with velocity of 100 ms^-1 penetrates 1 m into it. If the bullet is fired at a similar target with a thickness 0.5 m, then it will emerge from it with a velocity of

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$\frac{50}{\sqrt{2}} m / s$

$50 m / s$

$50 \sqrt{2} m / s$

$10 m / s$

answer is A.

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Detailed Solution

Let a be the deceleration of the bullet in both cases .

Then $100^{2} = 2 a \times 1 . . . . . . . . . . . . . . . (1)$

In the second case $v^{2} = 100^{2} - 2 a \times 0.5 . . . . . . . . . . . . . . (2)$

Solving , v = $50 \sqrt{2} m / s$

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