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A burglar $'$ s car had started with an acceleration of $2 m s^{- 2} .$ A police vigilant party came after $5 s$ and continued to chase the burglar $'$ s car with a uniform velocity of $20 m s^{- 1} .$ The time $($ in s $)$ taken in which the police van will catch the burglar $'$ s car is:

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$5 s$

$4 s$

$3 s$

$2 s$

answer is A.

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Detailed Solution

If $t$ is the time taken $,$ then $\frac{1}{2} \times 2 {(t + 5)}^{2} = 20 t$

After solving $, t = 5 s .$

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