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Q.

A bus starts from rest and moves with an acceleration of 1 m/s2. A boy, who is 48 m behind the bus run after with a constant speed of 10 m/s. The boy can catch the bus 

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a

only once, after 8 s form start

b

only once, after 12 s from start

c

twice after 8 sand12 s from start

d

never

answer is C.

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Detailed Solution

 48+12×1×t2=10t   t=8s and 12s. 

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