AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A bus starts from the rest and takes $50 s$ to get the speed of $10 m / s$ . If the mass of the bus along with passengers is $10000 kg,$ then the value of force is [[1]] $N$ applied by the engine of the bus to push the bus to the speed of $10 m / s$ .

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

A bus starts from the rest and takes

50 s

to get the speed of

10 m / s

. If the mass of the bus along with passengers is

10000 kg,

then the value of force is

2000 N

applied by the engine of the bus to push the bus at the speed of

10 m / s

.
Given:

M = 10000 kg

Velocity (initial)

u = 0 m / s

Final (velocity)

v = 10 m / s

Time

t = 50 s

Assuming the acceleration of the bus to be constant.
Using

v = u + at

(First Equation of uniformly accelerated motion)

∴ 10 = 0 + a (50)

\Rightarrow a = 0.2 m / s^{2}

Thus force required

F = ma

\Rightarrow F = 10000 \times 0.2

\Rightarrow F = 2000 N

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!