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Q.

A bus starts moving with acceleration 2 2. ms-2 A cyclist 96m behind the bus stats simultaneously towards the bus at 20 m/s. After what time will he be able to overtake the bus? (Least time in sec)

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answer is 8.

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Detailed Solution

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12×2×t2+96=20×t⇒t2−20t+96=0 

This gives,  t = 8 or 12sec.
Hence, the cyclist will overtake after 8sec.

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