A bus travels distance x1 when accelerates from rest at constant rate a1 for some time and after that travels a distance x2 when decelerates at a constant rate a2 to come to x1+x2=a1a2t22a1+a2. Choose the correct option(s).

LHS =x1+x2=x1=x2=M0LT0RHS=a1a2t22a1+a2 =LT−2LT−2T2LT−2=M0LT0∵ LHS = RHS According to homogeneity principle, equation is dimensionallycorrect.Hence, option (a) is correct.

A bus travels distance x1 when accelerates from rest at constant rate a1 for some time and after that travels a distance x2 when decelerates at a constant rate a2 to come to x1+x2=a1a2t22a1+a2. Choose the correct option(s).

LHS =x1+x2=x1=x2=M0LT0RHS=a1a2t22a1+a2 =LT−2LT−2T2LT−2=M0LT0∵ LHS = RHS According to homogeneity principle, equation is dimensionallycorrect.Hence, option (a) is correct.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A bus travels distance x₁ when accelerates from rest at constant rate a₁ for some time and after that travels a distance x₂ when decelerates at a constant rate a₂ to come to $x_{1} + x_{2} = \frac{a_{1} a_{2} t^{2}}{2 (a_{1} + a_{2})} .$ Choose the correct option(s).

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

The relation is dimensionally correct

The relation is dimensionally incorrect

The relation may be dimensionally correct

None of the above

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} LHS = [x_{1} + x_{2}] = [x_{1}] = [x_{2}] = [M^{0} L T^{0}] \\ \begin{aligned} RHS & = [\frac{a_{1} a_{2} t^{2}}{2 (a_{1} + a_{2})}] \\ = \frac{[L T^{- 2}] [L T^{- 2}] [T^{2}]}{[L T^{- 2}]} = [M^{0} L T^{0}] \\ ∵ LHS & = RHS \end{aligned} \end{array}$