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Q.

A cannon fires successively two shells with velocity 250 m/s. The first at an angle 600 and the second at the angle 450 to the horizontal, the azimuth being the same. Find the time interval between their firing so that the two shells collide in air. Assume no air friction. 

(in secs) (take g = 10m/s2(take  2  =1.414  &3=1.732) 

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answer is 10.72.

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Detailed Solution

From Horizontal direction
        u cos60 t1 = u cos450 t2 …………..1
   from vertical direction 
    u sin60 t1 – ½  gt12 = u sin 450 t2 – ½ gt22…………… 2
    From 1 & 2
     t1 =  2u(31)g
      t2 =  2u(31)g
      t1 - t2 = 10.72 sec

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