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Q.

A capacitor acquires a p.d. of 200V when 1012 electrons are taken from one plate and placed on the other plate. Its capacitance is

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a

12 × 10–10 m

b

4 × 10–10 m

c

2 × 10–10 m

d

8 × 10–10 m

answer is C.

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Detailed Solution

q=CV ; ne=CV ; 1012×1.6×10–19= C×200
C=0.8×10–9F

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