A capacitor C1 = 1μf and C2 = 2μf are charged with switch in position (1). Now switch is shifted to position (2). Capacitor C3 = 3μf is initially uncharged. The ratio of potential difference on C1 and C3 is:

8−q2+8−q−q3=0⇒q=72/11V1V3=16/1172/33=23

A capacitor C1 = 1μf and C2 = 2μf are charged with switch in position (1). Now switch is shifted to position (2). Capacitor C3 = 3μf is initially uncharged. The ratio of potential difference on C1 and C3 is:

8−q2+8−q−q3=0⇒q=72/11V1V3=16/1172/33=23

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A capacitor C₁= 1μf and C₂= 2μf are charged with switch in position (1). Now switch is shifted to position (2). Capacitor C₃ = 3μf is initially uncharged. The ratio of potential difference on C₁ and C₃ is:

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$\frac{1}{3}$

$\frac{2}{3}$

answer is B.

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$\begin{array}{l} \frac{8 - q}{2} + 8 - q - \frac{q}{3} = 0 \Rightarrow q = 72 / 11 \\ \frac{V_{1}}{V_{3}} = \frac{16 / 11}{72 / 33} = \frac{2}{3} \end{array}$

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A capacitor C1 = 1μf and C2 = 2μf are charged with switch in position (1). Now switch is shifted to position (2). Capacitor C3 = 3μf is initially uncharged. The ratio of potential difference on C1 and C3 is:

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A capacitor C₁= 1μf and C₂= 2μf are charged with switch in position (1). Now switch is shifted to position (2). Capacitor C₃ = 3μf is initially uncharged. The ratio of potential difference on C₁ and C₃ is: