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Q.

A capacitor is connected to a battery and the energy stored is U. The battery is now removed and the separation distance between the plates is doubled. The energy stored now is

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a

2U

b

4U

c

U

d

U/2

answer is C.

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Detailed Solution

$U = \frac{Q^{2}}{2 C}, C = \frac{ε_{0} A}{d}$

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