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Q.

A capacitor is connected to a cell. Electric field at a point in the space between the plates is Eo, energy stored in the capacitor is Uo, charge stored in the capacitor is Qo and capacitance of the capacitor is Co. When a slab of dielectric material ( dielectric constant k) b is introduced in the space between the plates, above quantities become E,U,Q and C. Then,
 

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a

E=Eo/k

b

Q=Qo

c

U=KUo

d

Both 1 and 2 are right.

answer is C.

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Detailed Solution

After the slab is introduced,
C=kC0 Q==(kC0)ε=kQo E=QAEoK2=KQo/AEoK=QotoA=Eo U=Q22C=(KQo)2(KCo)=K(Qo2/2Co)=KUo.

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