A capacitor of $20 μ F$ charged up to 200V is connected in parallel with another capacitor of $10 μ F$ charged to 100V with same polarity, then common potential is $\frac{x}{3} V .$ Find value of x.

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answer is 500.

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Detailed Solution

$V = \frac{C_{1} V_{1} + C_{2} V_{2}}{C_{1} + C_{2}} = \frac{20 \times 200 + 10 \times 100}{20 + 10} = \frac{5000}{30} V = \frac{500}{3} V \Rightarrow x = 500$

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