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Q.

A capacitor of capacitance C, having initial charge 2Q0, is connected to a battery of potential difference V=Q0Cas shown. The work done by the battery is  
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a

Q022C

b

3Q022C

c

3Q02C

d

2Q023C

answer is C.

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Detailed Solution

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Final potential difference between the plates, V=Q0C
Final charge on the originally negative plate of the capacitor, Q'=VC=Q0CC=Q0

Charge flowing through the battery, ΔQ=Q0(2Q0)=3Q0
Work done by battery,  W=ΔQV=3Q0Q0C=3Q02C

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