Q.

A capacitor of capacitance ‘C’ is charged with 'Q0' now it connected across a battery of e.m.f V=Q0C such that positive plate of capacitor connected with –ve end of battery and –ve plate with +ve end of battery then find energy supplied by battery before steady state condition obtained to capacitor is:

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a

Q022C

b

Q0C

c

32Q02C

d

2Q02C

answer is D.

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Detailed Solution

Δq=2Q0

Energy supplied =(Δq)V=2Q0Q0C

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